You are given an m x ngrid where each cell can have one of three values:
0 representing an empty cell,
1 representing a fresh orange, or
2 representing a rotten orange.
Every minute, any fresh orange that is 4-directionally adjacent to a rotten orange becomes rotten.
Return the minimum number of minutes that must elapse until no cell has a fresh orange. If this is impossible, return-1.
Example 1:
Input: grid = [[2,1,1],[1,1,0],[0,1,1]]
Output: 4
Example 2:
Input: grid = [[2,1,1],[0,1,1],[1,0,1]]
Output: -1
Explanation: The orange in the bottom left corner (row 2, column 0) is never rotten, because rotting only happens 4-directionally.
Example 3:
Input: grid = [[0,2]]
Output: 0
Explanation: Since there are already no fresh oranges at minute 0, the answer is just 0.
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 10
grid[i][j] is 0, 1, or 2.
public class Solution {
public int OrangesRotting(int[][] grid)
{
int n = grid.Length;
int m = grid[0].Length;
int fresh = 0;
Queue<(int, int)> queue = new Queue<(int, int)>();
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
if (grid[i][j] == 2)
{
queue.Enqueue((i, j));
}
else if (grid[i][j] == 1)
{
fresh++;
}
}
}
if (fresh == 0)
return 0;
int level = 0;
while (queue.Count > 0)
{
level++;
int size = queue.Count;
for (int i = 0; i < size; i++)
{
var (x, y) = queue.Dequeue();
if (x - 1 >= 0 && grid[x - 1][y] == 1)
{
queue.Enqueue((x - 1, y));
grid[x - 1][y] = 2;
fresh--;
}
if (x + 1 < n && grid[x + 1][y] == 1)
{
queue.Enqueue((x + 1, y));
grid[x + 1][y] = 2;
fresh--;
}
if (y - 1 >= 0 && grid[x][y - 1] == 1)
{
queue.Enqueue((x, y - 1));
grid[x][y - 1] = 2;
fresh--;
}
if (y + 1 < m && grid[x][y + 1] == 1)
{
queue.Enqueue((x, y + 1));
grid[x][y + 1] = 2;
fresh--;
}
}
}
return fresh > 0 ? -1 : level-1;
}
}